Question

method to solve the
Using, Triangularisation
folloksing equations
In 2x+ 3y +z=9
x + 2y +3z=6
3x + y + 2z=8
​

Answer 1

Answer:

GIVEN :

The equations are 2x+3y+z=9, x+2y+3z=6, 3x+y+2z=8​

TO FIND :

The values of x, y, and z in the given equations.

SOLUTION :

Given that the equations are

Now solving the equations (1) ,(2) and (3) by using Elimination method.

Multiply the equation (1) into 3

Now subtracting (4) by (2),

​6x+9y+3z=27

x+2y+3z=6

(-)_(-)_(-)_(-)___

_______________

Multiply the equation (1) into 2

Now subtracting (6) by (3),

4x+6y+2z=18

3x+y+2z=8​

(-)_(-)_(-)_(-)___

_______________

Now multiply the equation (7) into 5 we get,

Subtracting the equations (5) and (8)

5x+7y=21

5x+25y=50

(-)_(-)__(-)____

-18y=-29

∴  

Substitute the value of y in equation (5) we get

∴  

Substitute the values of x and y in equation (1) we get

∴  

∴ the values of x , y and z are  respectively.

∴  ,  and .

Explanation: