Question

Methods To Find Activation Energy .
chemistry​

Answer 1

Answer:

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Explanation:

Step 1: Convert temperatures from degrees Celsius to Kelvin. T = degrees Celsius + 273.15. T1= 3 + 273.15. ...

Step 1: Convert temperatures from degrees Celsius to Kelvin. T = degrees Celsius + 273.15. T1= 3 + 273.15. ...Step 2 - Find Ea ln(k2/k1) = Ea/R x (1/T1 - 1/T2) ln(7.1 x 10-2/8.9 x 10-3) = Ea/8.3145 J/K·mol x (1/276.15 K - 1/308.15 K) ...

Step 1: Convert temperatures from degrees Celsius to Kelvin. T = degrees Celsius + 273.15. T1= 3 + 273.15. ...Step 2 - Find Ea ln(k2/k1) = Ea/R x (1/T1 - 1/T2) ln(7.1 x 10-2/8.9 x 10-3) = Ea/8.3145 J/K·mol x (1/276.15 K - 1/308.15 K) ...Answer: The activation energy for this reaction is 4.59 x 104 J/mol or 45.9 kJ/mol.

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Answer 2

Answer:

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Explanation:

Step 1: Convert temperatures from degrees Celsius to Kelvin. T = degrees Celsius + 273.15. T1 = 3 + 273.15. ...

Step 2 - Find Ea ln(k2/k1) = Ea/R x (1/T1 - 1/T2) ln(7.1 x 10-2/8.9 x 10-3) = Ea/8.3145 J/K·mol x (1/276.15 K - 1/308.15 K) ...

Answer: The activation energy for this reaction is 4.59 x 104 J/mol or 45.9 kJ/mol.

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