Chemistry, asked by khuranarohankhurana, 2 months ago

Methyl benzoate is prepared by the reaction between benzoic acid and methanol, according to the equation 
C6​H5​COOH+CH3​OH⟶C6​H5​COOCH3​+H2​O
Benzoic acid     Methanol           Methyl benzoate
In an experiment 24.4 gm of benzoic acid were reacted with 70.0 mL of CH3​OH. The density of CH3​OH is 0.79gmL−1. The methyl benzoate produced had a mass of 21.6g. 

what is persentage conversion.​

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Answered by dev1568
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Answered by sanjanatambe09
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79.4%

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