methyl iodide read with sodium in the presence of dry ether
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Answer:
Ethane.
Explanation:
Wurtz reaction : Alkyl halide in the presence of sodium dry/ether react to give alkane(dimerised product).
Example 2CH₃X +2Na (Dry ether) ----------------> CH₂-CH₂ + 2NaX.
Therefore,
2CH₃I + 2 Na(Dry ether)------------->CH₂-CH₂ + 2NaI
Therefore the product is ethane.
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