Chemistry, asked by sdhok2555, 1 month ago



• Methyl lithium treated with dry ice gives
Answer
А.
tert-Butyl alcohol
tert-Butyl Chloride
Isopropyl alcohol
Isopropyl chloride
D.
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Answered by usmansami52
0

according to the experiment

Explanation:

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Answered by mindfulmaisel
1

If Methyl lithium is treated with Dry ice it will give Acetic Acid as product.

Formula of Methyl Lithium is CH₃Li and Dry ice is solidified CO₂ under proper conditions.

At first they both react to give Lithium acetate.

CH₃Li + CO₂ ⇄ CH₃CO₂⁻Li⁺

When it is treated with mild acid or acidic water it gives Acetic Acid as the product.

CH₃CO₂⁻Li⁺ + H⁺ ⇄ CH₃COOH

So, If Methyl lithium is treated with Dry ice it will give Acetic Acid (CH₃COOH) as product.

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