Question

_MgBr2 (aq) +_KOH(aq)..._KBr(aq) +Mg(OH)2 (s)​

Answer 1

Answer:

MgBr+2KOH-2KBr+Mg(OH)2

Answer 2

Answer:

MgBr2 (aq) + 2KOH (aq) (------- 2KBr (aq) + Mg(OH)2 (s)

Explanation:

there is 2 bromine in left side so add 2 digit before KBr now bromine is satisfied but K is remaining so Ad 2 digit before KOH left side NOW K is also satisfied

left            right

Mg (1)        Mg (1)

Br (2)         Br (2)

K  (2)          K(2)

OH(2)       OH (2)