Mia has a large bag of sweets.If she shares the sweets equally among 2,3,4,5 or 6 people there will always be 1 sweet left over.What is the smallest number of sweets there could be in the bag?
Answers
Answer:
The smallest no. of sweets meena has = LCM (2,3,4,5,6)+1 .
= 60 +1 =61 sweets
The smallest number of sweets is 61.
Step-by-step explanation:
Consider the provided information.
Mia has a large bag of sweets. If she shares the sweets equally among 2,3,4,5 or 6 people.
First find the LCM that will gives us the least number of sweets distributed equally among 2,3,4,5 or 6 people.
2 = 2
3 = 3
4 = 2 × 2
5 = 5
6 = 2 × 3
LCM = 2 × 2 × 3 × 5 = 60.
That means if she has 60 sweets, she can shares them equally among 2,3,4,5 or 6 people.
Now we want to be 1 sweet left over.
So add 1 and 60.
60+1=61.
Hence, the smallest number of sweets is 61.
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