Question

Michael finished colouring a picture in 7/12 hour. Vaibhav finished colouring the same picture in 3/4 hour. who worked longer? By what fraction was it longer?​

Answer 1

Step-by-step explanation:

Answer:-

Given:-

$Michael \: finished \: work \: in \: =  \: \frac{7}{12} \: hour$

$Vaibhab \: finished \: work \: in \: = \: \frac{3}{4}$

To find:-

• We need to find who worked longer.

Solution:-

i.e., we need to find greater of = 7/12 & 3/4

$We \: make \: their \: denominators \: equal -$

So,

$⟹ \: \frac{7}{12} \: \times \: \frac{1}{1} \: = \: \frac{7}{12}$

$⟹ \: \frac{3}{4} \: \times \: \frac{3}{3} \: = \: \frac{9}{12}$

$⟹ \: \frac{9}{12} \: > \: \frac{7}{12}$

$∴ Vaibhav \: worked \: longer.$

$We \: also \: need \: to \: find \: by \: how \: much \:$

$difference \: \: in \: \: hours \: =$

$= \: \frac{3}{4} \: - \: \frac{7}{12}$

$= \: \frac{9}{12} \: - \: \frac{7}{12 } \: [\frac{3}{4} \: = \: \frac{9}{12}]$

$= \: \frac{9 \: - \: 7}{12}$

$= \frac{2}{12}$

$= \frac{1}{6}$

$Hence \: Vaibhav \: worked \: longer \: by \: \frac{1}{6} \: hours.$