Math, asked by neelamknl778, 1 month ago

Michael finished colouring picture in 7/12 hours. Vaibhav finished colouring the same picture in 3/4 hours. Who worked longer? By what fraction was it longer?​

Answers

Answered by LSVAB
5

Answer:

Vaibhav worked longer by 1/6 hours.

Step-by-step explanation:

To find who worked longer,

7/12, 3/4

=LCM of 12,4 = 12,

=7/12, 3/4×3/3,

=7/12, 9/12

=7/12 < 9/12

=7/12 < 3/4

Therefore, Vaibhav worked longer.

To find by what fraction Vaibhav worked longer,

=3/4 - 7/12,

=9/12 - 7/12,

=2/12

=1/6 hours

Answered by Anonymous
4

Step-by-step explanation:

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Michael finished colouring picture in 7/12 hours. Vaibhav finished colouring the same picture in 3/4 hours. Who worked longer? By what fraction was it longer?

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Given:-

Time taken by Michael=

 \frac{7}{12}  \\

Time taken by Vaibhav=

 \frac{3}{4}  \\

 \frac{7}{12} and \:  \frac{3}{4}

LCM of 12 and 4= 12

 \frac{7}{12}  \times  \frac{1}{1}  =  \frac{7}{12}  \\  \frac{3}{4}  \times  \frac{3}{3}  =  \frac{9}{12}

Time taken by Michael to finish colouring=

 \frac{7}{12}

Time taken by Vaibhav to finish colouring=

 \frac{9}{12}

Maximum time taken=

 \frac{7}{12}  &lt;  \frac{9}{12}

More , Time was taken by Vaibhav to complete his colouring.

How much more Time was taken:-

Time taken by Vaibhav- Time taken by Michael

=> 9-7/12

=> 2/12

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