Question

Micheal in five times older than his son after 4 years the sum of their ages will be 44

Answer 1

Step-by-step explanation:

let the age of Micheal be x

let the age of his son be y

therefore

x=5y...............I

Now,

After 4 years

age of Micheal will be (x+4)years

and age of his son will be (y+4)years

they had given us the sum of ages

therefore

x+4+y+4=44

x+y=44-8

x+y=36...........II

put I in II

5y+y=36

6y=36

y=36/6

y=6

and

x=5y

x=5(6)

x=30

Therefore the age of Micheal is 30 years and of his son is 6 years.

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