Question

Michel has enough money to buy either 12 pears or 36 apples if he intends to buy an equal number of pears and apples,how many of each fruit can he buy with the money​

Answer 1

Explanation:

Let p be the price of pears, a be the price of apples and x be the amount of money that Michael has.

Let p be the price of pears, a be the price of apples and x be the amount of money that Michael has.Michael has enough money to buy 12 pears, excluding apples (given)

Let p be the price of pears, a be the price of apples and x be the amount of money that Michael has.Michael has enough money to buy 12 pears, excluding apples (given)x=12p

Let p be the price of pears, a be the price of apples and x be the amount of money that Michael has.Michael has enough money to buy 12 pears, excluding apples (given)x=12pMichael also has enough money to buy 36 apples, excluding pears (given)

Let p be the price of pears, a be the price of apples and x be the amount of money that Michael has.Michael has enough money to buy 12 pears, excluding apples (given)x=12pMichael also has enough money to buy 36 apples, excluding pears (given)x=12p=36a

Let p be the price of pears, a be the price of apples and x be the amount of money that Michael has.Michael has enough money to buy 12 pears, excluding apples (given)x=12pMichael also has enough money to buy 36 apples, excluding pears (given)x=12p=36aDivide both sides by 12

Let p be the price of pears, a be the price of apples and x be the amount of money that Michael has.Michael has enough money to buy 12 pears, excluding apples (given)x=12pMichael also has enough money to buy 36 apples, excluding pears (given)x=12p=36aDivide both sides by 12p=3a

Remove pears and add apples until you reach the same number of pears and apples

Remove pears and add apples until you reach the same number of pears and applesx=11p+3a

Remove pears and add apples until you reach the same number of pears and applesx=11p+3ax=10p+6a

Remove pears and add apples until you reach the same number of pears and applesx=11p+3ax=10p+6ax=9p+9a

Remove pears and add apples until you reach the same number of pears and applesx=11p+3ax=10p+6ax=9p+9aTherefore, he will be able to buy 9 pears and 9 apples.

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Answer 2

Answer:

So, 12:36

This is the same ratio as 1:3.

Now, we can set values for each. If Mike has enough money to buy 1 pear or 3 apples, we can set the price of a pear to $3 and the price of an apple to $1.

Now, we know he can only buy 12 pears or 36 apples, so let’s use our set price to solve this. 36*1 = 36, so he only has $36.

So, if he has only $36, then we can set an equation, assume x is the amount of apples and pears he wants. You want these values to be the same, so just set them to the same value which we we are calling x.

Then, 3x + x = 36. 3 is the amount of dollars for the pears and 1 is the amount of dollars for x.

4x = 36

x=9

By substituting some nice values into each of the problems, we can solve.

He will get 9 pears and 9 apples, and remember, the proportions will always remain the same, so this works for any type of money or amount of money.

Thanks, if you need any help, don’t be afraid to ask.

Hope this helps!

Explanation: