Question

Mid point of line segment joining A(2,4) and B(4,6) is

Answer 1

Answer:

Mid point of line joining A(2,4) and B(4,6)

= (2+4)/2 , (4+6)/2

=6/2, 10/2

=3,5

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Answer 2

$\Large\underline\mathfrak{Question}$

• Mid point of line segment joining A(2,4) and B(4,6) is ?

$\Large\bold\star\underline{\underline\textbf{Formula\:used}}$

• x = (x1+x2/2) , y = (y1+y2/2)

$\Large\underline{\underline{\sf{Solution}:}}$

Here,

→ x1 = 2, y1 = 4,

→ x2= 4, y2 = 6,

Putting values in formula we get,

→ x = (2+4)/2 = 3

→ y = (4+6)/2 = 5

Hence , Mid-Point of line segment are (3,5) ..

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$\large\bf\red\bigstar\underline\textbf{Extra\:Brainly\:Knowledge}\red\bigstar$ :-

✰) To find the distance between two points say P (x₁,y₁) and Q(x₂,y₂) is :

$\sqrt {{(x_2-x_1)}^{2}+{(y_2-y_1)}^{2}}$

✰) To find the distance of a point say P (x,y) from origin is :

$\sqrt {{x}^{2}+{y}^{2}}$

✰) Coordinates of the point P (x,y) which device the line segment joining the points A (x₁,y₁) and B (x₂,y₂)

internally in the ratio m₁ : m₂ is :

$\dfrac {m_1 x_2 + m_2 x_1}{m_1+m_2}$, $\dfrac {m_1 y_2 + m_2 y_1}{m_1+m_2}$

✰) The midpoint of the line segment joining the points P (x₁,y₁) and Q(x₂,y₂) is :

$\dfrac{x_1+x_2}{2}$ , $\dfrac{y_1+y_2}{2}$

✰) The area of the triangle formed by the points (x₁,y₁)(x₂,y₂) and (x_3,y_3) is the numerical value of the expression:.

$\dfrac{1}{2}[x_1(y_2-y_3)+x_2 (y_3-y_1)+x_3(y_1-y_2)]$

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#BAL

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