Math, asked by krishnapatel, 1 year ago

mid value of 60-80is

Answers

Answered by pulakmath007
0

The mid value of 60 - 80 is 70

Given :

The class interval 60 - 80

To find :

The mid value of the class interval 60 - 80

Concept :

Class Mark / Mid Value :

For any grouped frequency table with class intervals, the middle value of the class limits or the class boundaries of any class is called class mark or mid value of the class

Solution :

Step 1 of 3 :

Write down the given class interval

The given class interval is 60 - 80

Step 2 of 3 :

Write down Upper Class boundary & Lower class boundary

For the given class interval 60 - 80

Upper Class boundary = 80

Lower class boundary = 60

Step 3 of 3 :

Find mid value of the class interval

The mid value of the class interval

\displaystyle \sf{  =  \frac{Upper \:  Class \:  boundary  +  Lower \:  class  \: boundary }{2}  }

\displaystyle \sf{  =  \frac{80 + 60}{2} }

\displaystyle \sf{  =  \frac{140}{2} }

\displaystyle \sf{  =  70}

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Answered by sourasghotekar123
0

Answer:

The mid-value of the given interval (60-80) is 70.

Step-by-step explanation:

Given: The class interval of 60 - 80

To find: The mid-value of the given class interval

Mid Value - Also called the class mark of the respective interval, it is the middle value of the given interval with respect to its class limits.
Additionally, it is also known as the average value of the class limits of the given interval.

Formula - Class\;mark\;=\frac{class\; upper\; limit\;+\;class\;lower\;limit}{2}

Solution: To solve this question systematically, we follow 3 steps in the right order.

  1. We write down the class interval.
    In this case, it is 60-80.
  2. We then write down the upper and lower limits of the given interval.
    In our case, upper limit = 60; lower limit = 60
  3. Now that we have all the required information written down systematically, we use the aforementioned formula to find our answer.
    Class\;mark\;=\frac{class\; upper\; limit\;+\;class\;lower\;limit}{2}\;=\;\frac{80+60}{2}\;=\;70

Thus, we can conclude that the mid-value of the given class interval is 70.

#SPJ2

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