Question

mid value of class 1-9 is

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Answer 1

Answer:

1+9/2 = 5

upper limit+ lower limit/2

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Answer 2

SOLUTION

TO DETERMINE

The mid value of the class 1 - 9

CONCEPT TO BE IMPLEMENTED

Class Interval

When the number of sample values are large in number and are in wide range, then the whole data is divided in a number of several groups according to the size of the sample. Each of these groups, made as above, is known as class interval

Class Mark / Mid Value

For any grouped frequency table with class intervals, the middle value of the class limits or the class boundaries of any class is called class mark of the class

EVALUATION

Here the given class is 1 - 9

So the required mid value of the class

$\displaystyle \sf{ = \frac{1 + 9}{2} }$

$\displaystyle \sf{ = \frac{10}{2} }$

= 5

FINAL ANSWER

The mid value of the class 1 - 9 = 5

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