Middel term explating of this equation 8x^2-21x-72=0
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8x^2+-21x-72=0
Solving 8x2-21x-72 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 8
B = -21
C = -72
Accordingly, B2 - 4AC =
441 - (-2304) =
2745
Applying the quadratic formula :
21 ± √ 2745
x = ——————
16
Can √ 2745 be simplified ?
Yes! The prime factorization of 2745 is
3•3•5•61
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 2745 = √ 3•3•5•61 =
± 3 • √ 305
√ 305 , rounded to 4 decimal digits, is 17.4642
So now we are looking at:
x = ( 21 ± 3 • 17.464 ) / 16
Two real solutions:
x =(21+√2745)/16=(21+3√ 305 )/16= 4.587
or:
x =(21-√2745)/16=(21-3√ 305 )/16= -1.962
Two solutions were found :
x =(21-√2745)/16=(21-3√ 305 )/16= -1.962
x =(21+√2745)/16=(21+3√ 305 )/16= 4.587
Solving 8x2-21x-72 = 0 by the Quadratic Formula .
According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :
- B ± √ B2-4AC
x = ————————
2A
In our case, A = 8
B = -21
C = -72
Accordingly, B2 - 4AC =
441 - (-2304) =
2745
Applying the quadratic formula :
21 ± √ 2745
x = ——————
16
Can √ 2745 be simplified ?
Yes! The prime factorization of 2745 is
3•3•5•61
To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).
√ 2745 = √ 3•3•5•61 =
± 3 • √ 305
√ 305 , rounded to 4 decimal digits, is 17.4642
So now we are looking at:
x = ( 21 ± 3 • 17.464 ) / 16
Two real solutions:
x =(21+√2745)/16=(21+3√ 305 )/16= 4.587
or:
x =(21-√2745)/16=(21-3√ 305 )/16= -1.962
Two solutions were found :
x =(21-√2745)/16=(21-3√ 305 )/16= -1.962
x =(21+√2745)/16=(21+3√ 305 )/16= 4.587
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