Question

Middle tefm split x^2+2root2x-6

Answer 1

"X^2 + 2root2 x-6 = x^2+3 root2x - root2x - 6

Given, x²+2√2 x -6 = 0

by splitting,⇒x²+3√2 x- √2x -6 = 0

If x=3q+2 Squaring both sides

X^2=(3q+2) = 9q^2+12q+4

We squared 3 3X3=9

With taking the difference between them then it would be 0 and especially based on different aspects with enabling more attributes to the high excellence.

"

Answer 2

Answer:

Hi there !!

p(x) = x² + 2√2x - 6

We can find the zeros by factorization [ by splitting the middle terms ]

x² + 2√2x - 6

x² + 3√2x - √2x - 6

x [ x + 3√2 ] - √2 [ x+ 3√2]

[ x - √2 ] [ x+ 3√2]