Question

Middle term of the expansion (x^2+1/x)^2n is 924x^6 then n is

Answer 1

Answer:

12

Step-by-step explanation:

Given If the middle term in the expansion of (x^2+1/x)^n is 924x^6 then n =

There is one middle term. So let middle term be n/2.

Now middle term will be n C n/2 (since r will be middle term)

So n Cn/2 (x^2) ^n – n/2 (1/x)^n/2

     So n Cn/2 x x^2n/2 . 1/x^n/2

        n Cn/2 . x ^n – n/2

       n Cn/2 . x^n/2

        = 924 x^6 (n/2 = 6)

        n/2 = 6

       n = 12

We can see that 12 C6 will be equal to 924

Answer 2

Answer:

12 is the answer.

Step-by-step explanation:

Given If the middle term in the expansion of (x^2+1/x)^n is 924x^6 then n =

There is one middle term. So let middle term be n/2.

Now middle term will be n C n/2 (since r will be middle term)

So n Cn/2 (x^2) ^n – n/2 (1/x)^n/2

So n Cn/2 x x^2n/2 . 1/x^n/2

n Cn/2 . x ^n – n/2

n Cn/2 . x^n/2

= 924 x^6 (n/2 = 6)

n/2 = 6

n = 12