Math, asked by bodhik9, 1 year ago

Middle term split
root3x^2 + 10x + 7root3

Answers

Answered by Anonymous
24

Sum = 10

Product = √3 × 7√3 = 7(√3)^2 = 7×3 = 21

Two numbers with sum as 10 and product as 21 are 7 and 3.

Factorisation -

 \sqrt{3}  {x}^{2}  + 10x + 7 \sqrt{3}   \\  \\  \sqrt{3}  {x}^{2}  + (7 + 3)x + 7 \sqrt{3}  \\  \\  \sqrt{3}  {x}^{2}  + 7x + 3x + 7 \sqrt{3}  \\  \\  \sqrt{3}  {x}^{2}  + 7x + ( \sqrt{3}  {)}^{2} x + 7 \sqrt{3}  \\  \\ x( \sqrt{3} x + 7) +  \sqrt{3} ( \sqrt{3} x + 7) \\  \\ (x +  \sqrt{3} )( \sqrt{3} x + 7)

Answered by legocreations20
2

Please see the attached document for the answer...

Ignore my bad handwriting....

ANSWER:

 (\sqrt{3} x +  7)(x +  \sqrt{3} )

Attachments:
Similar questions