midpoint for (-2,-4) (-2,8)
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Answer:
(-2,-6)
because by calculating its midpoint you should have used its formula which is
[(x1 + x2)/2, (y1 + y2)/2]
= [(-2 + (-2))/2 , (-4 + (-8))/2]
= [(-2 - 2)/2 , (-4 - 8)/2]
= [-4/2 , -12/2]
= (-2 , -6)
Therefore its midpoint is equal to (-2,-6).
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