Mikal is proving that AE ≅ CE . Triangles A B E and C D E are connected at point E. Angles A B E and E D C are right angles. The lengths of A C and D C are congruent. Which reason does the ♣ represent in Mikal’s proof? SAS SSS ASA AAS
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AAS is the right answer
Step-by-step explanation:
Correction AB = DC instead of AC = DC ( refer picture)
AB = DC (given)
∠ABE & ∠EDC are right angles
=> ∠ABE = ∠EDC = 90°
∠AEB = ∠CED ( oppsoite angle)
=> ΔABE ≅ ΔCDE ( based on AAS)
=> AE = CE
♣ represent AAS in Mikal’s proof
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