Question

Mike needs 30% to pass. If he scored 212 marks and falls short by 13 marks, what was the maximum marks he could have got?

Answer 1

A.T.Q

30 per cent of x is 230

then 30/100 ×x =230

30x/100 =230

30x = 2300

x= 23000/30

=767 approx

Answer 2

Let the maximum marks be m.

Then 30 % of m = 225

(30/100) × m = 225

m = (225 × 100)/30

m = 22500/30

m = 750