Mike travels in an airplane a distance of 2760 miles.For one half of the distance, the airplane flies at a speed of 560 miles per hour, and for rest of the distance. it flies at a speed of 820 mph.How long does the trip take.
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for first half of the distance,
d = 2760/2 = 1380 miles
speed = 560 mph
time(t₁) = 1380/560 = 2.464 hour
for second half of the distance,
d = 2760/2 = 1380 miles
speed = 820 mph
time(t₂) = 1380/820 = 1.683 hour
total time = t₁ + t₂ = 2.464 + 1.683 = 4.147 hours
d = 2760/2 = 1380 miles
speed = 560 mph
time(t₁) = 1380/560 = 2.464 hour
for second half of the distance,
d = 2760/2 = 1380 miles
speed = 820 mph
time(t₂) = 1380/820 = 1.683 hour
total time = t₁ + t₂ = 2.464 + 1.683 = 4.147 hours
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