Milena and Mashuka, working together, can complete ajob in 9 days. However, Mashuka works alone and leaves after completing two-fifths of the job. Then Milena takes over and completes the remaining work by herself. As a result the duo could complete the job in 19.5 days. How many days would Milena alone have taken to do the job if Mashuka worked faster than Milena?
Answers
Milena alone would have taken 15 days to do the job
Step-by-step explanation:
Let Milena can complete a job in x days and Mashuka can complete the job in y days
Work done by Milena in 1 day = 1/x
Work done by Mashuka in 1 day = 1/y
Togather in 1 day Milena and Mashuka can do job
The both can complete the job together in 9 days
Therefore,
............. (1)
Let Milena completes 2/5 of work in a days and Mashuka compeltes remaining 1/5 work in b days
Then
Similarly,
According to the question
............... (2)
Multiplying eq (1) by 2 and subtracting it from eq (2)
We get
...... (3)
Putting the value of x in eq (1)
Putting the value of y in eq (3)
But it is given that Mashuka works faster than Milena
Therefore, taking and putting it in eq (3)
Therefore, Milena alone would have completed the job in 15 days.
Hope this answer was helpful.
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Answer:
Step-by-step explanation: