Math, asked by rathoreruby18, 6 hours ago

Milk costing Rs.30/litre is mixed with another variety costing Rs.80 a litre in a particular ratio such that when it is sold at Rs.72/litre, there is a profit of 20%. In what ratio were the 2 solutions mixed?

Answers

Answered by kavitakushwaha1981
0

Answer:

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Step-by-step explanation:

If two types are equally mixed the average rate per liter will be

(30/L+80/L)/2=55/L

Now

Let x and y are fractions to be mixed in such a way that, if mixture is sold at 72 /L it will give 20% profit with respect to 55/L

Let x is fraction 30/L type

y=1-x is fraction for 80/L type

Therefore,

x*30+(1-x)*80=1.2x 55

Solving this we get

x= 0.28 and

y=0.72

Thus ,

0.28x30+0.72x80= 66/L rate of mixture milk

Hence two types of milk are to be mixed in proportion

0.28 and 0.72 for 30/L milk and 80/L milk respectively.

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