Question

Milk in in a container which is in the form of a frustum of a cone of height 30 cm and the radius of whose lower and upper circular ends are 20 cm and 40 cm respectively is to be distributed in a camp for flood victims if this milk is available @ rupees 30 per litre and 880 litre of milk is needed for a camp find how many such containers of milk are needed for a camp and what cost will it put on the donor agency for this

Answer 1

Given--Radius of lower end (R1) = 20cm
            Radius of upper end (R2)= 40 cm
            Height (H)= 30 cm

So the volume of container= 1/3 pi H ( R1² + R2² + R1R2)
                                          = 1/3 * 22/7 * 30 ( (20)² + (40)² + 40* 20)
                                          = 1/3 * 22/7 * 30 ( 400 + 1600 + 800)
                                          = 1/3* 22/7 * 30 * 2800
                                          = 88000 cm³ or 88 litres.

Amount of milk required = 880 litre
No. of containers needed will be= 880/88= 10 containers. 

Cost of 1 litre milk= Rs. 30
So, Cost of 880 litre= 880 * 30 = Rs. 26400

Answer 2

Answer:

Step-by-step explanation: