Milk in in a container which is in the form of a frustum of a cone of height 30 cm and the radius of whose lower and upper circular ends are 20 cm and 40 cm respectively is to be distributed in a camp for flood victims if this milk is available @ rupees 30 per litre and 880 litre of milk is needed for a camp find how many such containers of milk are needed for a camp and what cost will it put on the donor agency for this
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Answered by
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Given--Radius of lower end (R1) = 20cm
Radius of upper end (R2)= 40 cm
Height (H)= 30 cm
So the volume of container= 1/3 pi H ( R1² + R2² + R1R2)
= 1/3 * 22/7 * 30 ( (20)² + (40)² + 40* 20)
= 1/3 * 22/7 * 30 ( 400 + 1600 + 800)
= 1/3* 22/7 * 30 * 2800
= 88000 cm³ or 88 litres.
Amount of milk required = 880 litre
No. of containers needed will be= 880/88= 10 containers.
Cost of 1 litre milk= Rs. 30
So, Cost of 880 litre= 880 * 30 = Rs. 26400
Radius of upper end (R2)= 40 cm
Height (H)= 30 cm
So the volume of container= 1/3 pi H ( R1² + R2² + R1R2)
= 1/3 * 22/7 * 30 ( (20)² + (40)² + 40* 20)
= 1/3 * 22/7 * 30 ( 400 + 1600 + 800)
= 1/3* 22/7 * 30 * 2800
= 88000 cm³ or 88 litres.
Amount of milk required = 880 litre
No. of containers needed will be= 880/88= 10 containers.
Cost of 1 litre milk= Rs. 30
So, Cost of 880 litre= 880 * 30 = Rs. 26400
lasya12:
thank u very much..it helped me a lot
Anytime:)
hi
shouldnt we multiply cost with 88 litres...plz help
Yes my question is also the same plz tell
no as 880l is required so
and rate is 35 per l
Nope in the question it is 30 rupees
In the question itself has given about 880litres then wht is the confusion about
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