Question

milk of any tanker
6. Two bills of 6075 and 8505 respectively
are to be paid by cheques of the same amount.
what will be the largest possible amount of each
cheque?
220 313​

Answer 1

Answer:

1215

Step-by-step explanation:

Largest possible amount of cheque will be the HCF(6075,8505).

Applying Euclid's division lemma to 8505 and 6075, we have

8505=6075×1+2430

Since, remainder 2430 is not equal to 0.

Again applying division lemma to 6075 and 2430

6075=2430×2+1215

Again remainder 1215 is not equal to 0.

So, again applying the division lemma to 2430 and 1215

2430=1215×2+0

Here the remainder is zero

So, HCF=1215

Therefore, the largest possible amount of each cheque will be 1215.