Question

milk powder comes in a cylindrical container whose base has a diameter of 14cm and height of 20 cm find its volume.
​

Answer 1

Volume of cylinder  = $\bf 3080cm^3$

${\large{\underline{\underline{\textbf{Given :}}}}}$

$\text{diameter}=\text{14 cm}$

$\text{height}(h) = \text{20 cm}$

${\large{\underline{\underline{\textbf{To Find :}}}}}$

$\text{Volume of cylinder}$

${\large{\underline{\underline{\textbf{Formula Applied :}}}}}$

$\text{Volume of cylinder} = \pi r^{2} h$

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{7cm}}\put(9,17.5){\sf{20cm}}\end{picture}$

${\large{\underline{\underline{\textbf{Solution :}}}}}$

To find volume we need to know radius of cylinder.

$\text{radius} = \frac{\text{diameter}}{2} \implies \frac{14}{2}$

$\text{radius (r)} = 7cm$

$\text{Volume } = \pi r^{2} h \implies \frac{22}{7} \times 7 \times 7\times 20$

$\text{Volume}= 22 \times 7 \times 20$

$\text{Volume} = 140 \times 22$

$\text{Volume} = 3080\:cm^3$

Answer 2

QUESTION:-

Milk powder comes in a cylindrical container whose base has a diameter of 14cm and height of 20 cm. Find its volume.

REQUIRED ANSWER:-

$\bf \red {Given:-}$

$\sf{Diameter \: of \: Cylinder = 14 cm}$

$\sf{Height \: of \: Cylinder = 20 cm}$

$\bf \red {To \: Find:- }\sf{Volume \: of \: milk \: powder \: in \: container}$

Diagram:-

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{7cm}}\put(9,17.5){\sf{20cm}}\end{picture}$

$\large \qquad \quad { \pink{ \bigstar}}{ \underline{\sf {According \: to \: Question:- }}}$

↦Volume of Milk powder = Volume of container

$\dag { \boxed{ \sf{ \purple{Volume \: of \: Cylinder = \pi {r}^{2} h}}}}$

Note.! :- Here 'r' and 'h' are 'radius' and 'height' of the cylinder respectively.

↦Let us now put all the values in the formula.

$\rightarrow \sf{ Volume = \pi {r}^{2}h }$

$\rightarrow \sf{ Volume = \frac{22}{7} \times {14}\times 20 }$

$\rightarrow \sf{ Volume = \frac{22}{7} \times {7 \times 7}\times 20 }$

$\rightarrow \sf{ Volume = 22 \times {7}\times 20 }$

$\rightarrow \sf{ Volume = 154\times 20 }$

$\rightarrow \sf{ Volume = 3080}$

$\sf {Volume \: of \: Cylinder = {3080cm}^{3} }$

$\huge { \boxed{ \underline{ \frak{ \pink{ So, the \: volume \: of \: Cylinder \: is \: {3080cm}^{3} }}}}}$

$\rule{300}{1.5}$

EXPLORE MORE:-

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$

Note..!!

• Please see the above formats in web as they may not be visible in the app.
• If you have any problem to see them in web refer to the above attachment.
• Full formula not visible? Side the page to see full formulas.

$\rule{300}{1.5}$