Question

milk tanker cylindrical in shape having diameter 2m and length 4.2m supplies milk in the two booths in the ratio 3:2. One of the milk booths has cuboidal vessel having base area 3.96 sq.m.and othee has cylindrical vessel having radius 1m. Find the level of milk in each of the vessels.

Answer 1

Let A represent vessel with base area of 3.96m2 and B that with base radius of 1m

The milk is divided in the ratio :A:B which is 3:2

Getting the volume of the milk :1×3.142×4.2= 13.1964m3

According to the ratio: A gets 3/5×13.1964=7.918m3

B gets 2/×13.1964=5.279m3

Height for A is: volume/base area=7.918/3.96=1.999m

Height of B : we first get the base area :1×3.142=3.142

The height is:5.279/3.172=1.68m

Answer 2

Answer:

Step-by-step explanation:

Let A be the vessel with base area and

B that with base radius

The milk is divided in the ratio :A:B which is 3:2

So,3+2=5

Getting the volume of the milk :1×3.142×4.2= 13.1964m3

According to the ratio: A gets 3/5×13.1964=7.918m3

B gets 2/×13.1964=5.279m3

Height for A is: volume/base area=7.918/3.96=1.999m

Height of B : we first get the base area :1×3.142=3.142

The height is:5.279/3.172=1.68m

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