Question

Milliequivalent of baoh2 present in 100 ml solution having ph. 13

Answer 1

Answer:

Explanation:

​  

 

Given, pH=13

Now, [H  

+

]=10  

−13

 

[OH  

−

]=10  

−1

 

10  

−1

=  

Gramequivalentwt.

weight

​  

×  

100

1000

​  

 

=  

1000

10  

−1

×100

​  

 

=10  

−2