Question

mina takes 10 minutes 15 seconds to go to school from home and tina takes 12 minutes 10 sec onds. how much time tina takes more than mina

(A) 2 minutes 5 seconds .

(B) 22 minutes 25 seconds .

(C) 1 minute 5 seconds.

(D) 1 minute 55 seconds.​

Answer 1

Step-by-step explanation:

time taken by mina=10 min 15 sec

time taken by tina=12min 10 Sec

difference= time taken by tina - time taken by mina

=12 min 10 sec - 10 min 15 sec

=1 min 55sec

therefore, tina takes 1 min 55 sec more than mina

Answer 2

Given: Mina takes 10 minutes 15 seconds to go to school from home and Tina takes 12 minutes 10 seconds.

To find: Amount of time Tina takes more than Mina.

Solution:

• In order to find the time taken by Tina more than Mina, the two time durations given must be subtracted.
• These time intervals are converted into seconds before subtracting.
• For 10 minutes 15 seconds,

        $(10 * 60) + 15 = 615 s$

• For 12 minutes 10 seconds,

        $(12 * 60) + 10 = 730 s$

• On subtracting, the difference obtained is,

        $730s - 615s = 115s$

• Now, 115 s is converted to minutes and seconds.
• It is equal to 1 minutes 55 seconds.

Therefore, Tina takes 1 minutes 55 seconds more than Mina.