Math, asked by ykeerthana2007, 1 day ago

Minakshi asks Sundaram to think of a 2-digit number, and then to do whatever she asks him to do, to that number. Their conversation is given in terms of questions .pick the answer correctly. 1) Choose a 2- digit number. a) Ab b) 10a + b c) 10a+10b d) a+b. 2)Reverse the digits to get a new number. a) ba, b) 10 +ab c) 10b + a d) b + a . 3) Add this to the number you have started with . a) ab + ba, b) 11a + 11b c)10a + 10b d) a + b. 4)Now divide the number with 11. Then the remainder is a) 1 b) 0 C) 11 d) 10. 5)The quotient is a) a b) b c) a + b d) 0.​

Answers

Answered by 31aliahmedzahidshaik
0

Answer:

Minakshi asks Sundaram to think of a 2-digit number, and then to do whatever she asks him to do, to that number. ... So, he got the reversed number 94; then he added these two numbers and got 49 + 94 = 143. Finally he divided this number by 11 and got 143 ÷ 11 = 13, with no remainder.

Answered by COMMANDED
0

Answer:

Minakshi asks Sundaram to think of a 2-digit number, and then to do whatever she asks him to do, to that number. ... So, he got the reversed number 94; then he added these two numbers and got 49 + 94 = 143. Finally he divided this number by 11 and got 143 ÷ 11 = 13, with no remainder.

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