Question

Ming throws a stone off a bridge into a river below.
The stone's height (in meters above the water), xx seconds after Ming threw it, is modeled by:
h(x)=-5(x-1)^2+45h(x)=−5(x−1)
2
+45
How many seconds after being thrown will the stone reach its maximum height?

Answer 1

Answer:

In 1 second stone reach its maximum height.

Step-by-step explanation:

Ming throws a stone off a bridge into a river below.

The stone's height ( in meter above the water)

$h(x)=-5(x-1)^2+45$

It is parabolic equation. Maximum height should be at vertex.

This is equation inform of vertex form,

$y=a(x-h)^2+k$

Vertex: (h,k)

Vertex of given path $h(x)=-5(x-1)^2+45$ (1,45)

Maximum height = 45 meter

Maximum height at x=1 seconds.

Thus, In 1 second stone reach its maximum height.