Question

MINH
If s= t^3- 4t^2+5 describes the motion
of particle, then its velocity when the
acceleration vanishes, is
i)16/9 unit/sec
iii) 4/3 unit/sec
ii) -32/3 unit/sec
iv) -16/3 unit/sec​

Answer 1

Answer:

by double differentiating,we get

a=d^2s/dt^2=6t-8=0

t=4/3

therefore,the velocity =ds/dt=3t^2-8t

=3(4/3)^2-8(4/3)

=16/3-32/3

=-16/3 unit/sec

therefore,option(iv) is correct

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