Question

Minimize: C = 100X + 80Y subject to 40X + 60Y greater than or equal to 360, 20X + 60Y greater than or equal to 240, 1600X + 1200Y greater than or equal to 9600, X greater than or equal to 0, Y greater than or equal to 0. Determine the point (X, Y) that gives the minimum value of C.

Answer 1

Answer:Determine the point (x, y) that gives the minimum value of C. Minimize: C = 100x + 80y Subject to: 40x + 60y2 360 20x + 60y2 240 1600x + 1200y9600 X, y 20 O (0,4) (3, 4) O (6, 2) O.(0,6) of the tested

Step-by-step explanation:

Answer 2

Given:

The minimize in the $C=100x+80y$ subject to $40x+60y$ grater than or equal to $360,20x+60y$ grater than or equal to $240$, $1600x+1200y$ grater than or equal to $9600$.

To find:

The point $(x,y)$ that the minimum value of c.

Step-by-step explanation:

$40x+60y=360$

$20x+60y=240$

$1600x+1200y\geq 9600$

$x\geq 0,y\geq 0$

$2x+3y\geq 18$

$x+3y\geq 12$

$4x+3y\geq 24$

$x\geq 0,y\geq 0$

$A(0,8)$

$C=640$

$B(3,4)=C=620$

$Q(6,2)=C=760$

$P(12,0)=C=1200$

Answer:

Therefore, the minimum value of c is 620.