Minimize the following boolean function-
F(A, B, C) = Em(0,1,6,7) + Ed(3, 5)
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Explanation:
Minimize the following boolean function-
F(A, B, C) = Em(0,1,6,7) + Ed(3, 5)
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The minimized boolean expression is-
F(A, B, C) = AB + A’B’
Given,
F(A, B, C) = Em(0,1,6,7) + Ed(3, 5)
To Find,
We have to find the minimize form of the Boolean function - F(A, B, C) = Em(0,1,6,7) + Ed(3, 5)
Solution,
- Since the given boolean expression has 3 variables, so we draw a 2 x 4 K Map.
- We fill the cells of K Map in accordance with the given boolean function.
- Then, we form the groups in accordance with the above rules.
Now, we have to follow the above picture
Now,
F(A, B, C)
= A'(B’C’ + B’C) + A(BC + BC’)
= A’B’ + AB
Then the minimized boolean expression is-
F(A, B, C) = AB + A’B’
- It may be noted that there is no need of considering the quad group.
- This is because even if we consider that group, we will have to consider the other two duets.
- So, there is no use of considering that quad group.
Hence, the minimized boolean expression is- F(A, B, C) = AB + A’B’
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