Math, asked by fzn1786, 2 months ago

Minimize Z = 20x + 70y
Subject to constraints : 2x + y ≥ 8, x + 2y ≥ 10, x ≥ 0, y ≥ 0​

Answers

Answered by bhagyashreehappy123
2

First we draw the lines x + 2y = 40, 3x + y = 30, 4x + 3y = 60 The feasible region(shaded region) is the bounded region "EAQPA'' The vertices of the region are E(15,0), A(40,0), Q(4,18) and P(6,12) Given objective function is z = 20x + 10y At, E(15,0), z = 300 At, A(40,0), z = 800 At, Q(4,18), z = 260 At, P(6,12), z = 240 Hence, Zmin = 240 at x = 6, y = 12Read more on Sarthaks.com - https://www.sarthaks.com/590094/minimize-20x-10y-subjected-to-x-2y-40-3x-y-30-4x-3y-60-x-0-y-0

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