Question

minimum and maximum value for a quadratic equations
f(X)=4x^2+2x-7​

Answer 1

Step-by-step explanation:

range of a quadratic equation is

(-D/4a,+oo)

where D is b^2-4ac

so D = 4-4(4)(-7) = 116

-D/4a = -116/16 = -7.25

so minimum value -7.25 and maximum +oo

hope it helps u

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