Minimum atomic number which can change the present model of periodic table?
1) 119
2) 121
3) 132
4) 144
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you can see that last elements in 7th group is Og which atomic no is 118 .
if next element , I mean element which atomic number = 119
then , a new period will require for this elements
another way ,
maximum no of elements in 1st peroid = 2
maximum no of elements in 2nd period =8
max no of elements in 3rd period = 8
max no of elements in 4th peroid = 18
max no of elements in 5th period = 18
max no of elements in 6th peroid = 32
max no of elements in 7th peroid = 32
==================================
total no of elements = 118
hence, next 8th peroid for new elements which atomic no = 119
if next element , I mean element which atomic number = 119
then , a new period will require for this elements
another way ,
maximum no of elements in 1st peroid = 2
maximum no of elements in 2nd period =8
max no of elements in 3rd period = 8
max no of elements in 4th peroid = 18
max no of elements in 5th period = 18
max no of elements in 6th peroid = 32
max no of elements in 7th peroid = 32
==================================
total no of elements = 118
hence, next 8th peroid for new elements which atomic no = 119
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Answered by
4
Answer:
121 element is the correct answer.
Explanation:
Present form periodic table has 7 periods. So, in order to change the present form of periodic table there should be 8 periods.
Now for 8th period,
we know,
energy levels are as follows: 8s 5g 6f 7d 8p *
now, as we start filling the electrons, 119th & 120th element/electron will come under 's-subshell' or 's' group/block which is not a new form it already exist in the modern periodic table. Now, as we further fill 121th element/electron in the 5g subshell, we get a new block i.e g-block.
Therefore, minimum atomic number which can change the present model of periodic table is 121.
*note:
How we decide the energy level of a period "nth"?
for that:
write: ns '''''''''''(n-2)g (n-1)f (n-1)d np.
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