Minimum distance between two tetrahedral voids if a is the edge length of the cube is
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Answer: a/2
Explanation:
As shown in figure, if we divide a FCC unit cell into 8 small cubes, then each small cube has 1 Tetrahedral void at its own body centre.
Thus, there are total 8 Tetrahedral voids in one unit cell.
It can also be seen from the figure that the nearest distance between two Tetrahedral voids is a/2.
Hope your doubt is clear now...!!!
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