Minimum frequenty required to remove electron from Cs metal is 4.6 x 10^14 Hz then what will be minimum energy of Photon use to remove electron? What will be work function of metal Also find threshold wavelength?
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Minimum frequenty required to remove electron from Cs metal is 4.6 x 10^14 Hz then what will be minimum energy of Photon use to remove electron? What will be work function of metal Also find threshold wavelength?
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Answered by
2
Energy of incident radiation is E=
λ
hc
=
3×10
−7
6.6×10
−34
×3×10
8
=6.6×10
−19
J.
Also, work function is ϕ=2×1.6×10
−19
J=3.2×10
−19
J.
Hence, maximum kinetic energy of emitted photo electrons will be 6.6×10
−19
J−3.2×10
−19
J=3.4×10
−19
J
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