Chemistry, asked by Anonymous, 5 hours ago

Minimum frequenty required to remove electron from Cs metal is 4.6 x 10^14 Hz then what will be minimum energy of Photon use to remove electron? What will be work function of metal Also find threshold wavelength? ​

I am so confused too
Cause Eberyone is asking me bout my true identity
:/

Yeash I am asiandomb and mrdomb
:D

#bill gates of brainly with less points​

Answers

Answered by ShinzoKato
4

Minimum frequenty required to remove electron from Cs metal is 4.6 x 10^14 Hz then what will be minimum energy of Photon use to remove electron? What will be work function of metal Also find threshold wavelength?

No , I am not asking from you

I know who are you ,I am Tanvi

Answered by sruthikajagadeesan20
2

Energy of incident radiation is E=

λ

hc

=

3×10

−7

6.6×10

−34

×3×10

8

=6.6×10

−19

J.

Also, work function is ϕ=2×1.6×10

−19

J=3.2×10

−19

J.

Hence, maximum kinetic energy of emitted photo electrons will be 6.6×10

−19

J−3.2×10

−19

J=3.4×10

−19

J

mark me as brainliests and whose is the bill gates of brianly ? !

Similar questions