Question

minimum must be added to 2x3 3x2 + 6x + 7 so that the resulting
polynomial will be divisible by x2 - 4x + 8?​

Answer 1

-10x + 33 requires to be added to 2x^3 - 3x^2 + 6x + 7.

Step-by-step explanation:

Let

p(x) = 2x^3 - 3x^2 + 6x + 7

If we divide p(x) is divided by x^2 - 4x + 8, then r(remainder) = 0

By dividing 2x^3 - 3x^2 + 6x + 7 by x^2 - 4x + 8, we get;

Quotient = 2x + 5

Remainder = 10x - 33

Since a + 10x - 33 = 0

Thus,

- 10x + 33 is the minimum required to be added.                    

Learn more: Polynomials

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