Question

minimum number of capacitors of 2 microfarad is required to obtain a capacitance of 5 microfarad will be

Answer 1

Minimum number of capacitor of 2uf each required to obtain a capacitance of 5uf will be 4

Answer 2

ans : 4

if two capacitors will be in series and two capacitors will be in parallel as shown in figure then, equivalent capacitance will 5 microfarad.

Let see AB and BC capacitors are in series
so, equivalent capacitance {X} of it = 2microfarad/2 = 1 microfarad { in series 1/Ceq = 1/C1 + 1/C2}

DE and GF capacitors are in parallel ,
so, equivalent capacitance { Y} of it = 2 + 2 = 4 microfarad { in parallel, Ceq = C1 + C2 }

now, X and Y capacitors are in parallel then,
Ceq = 4 + 1 = 5 microfarad.

hence, minimum number of capacitors = 4