Minimum number of capacitors of 2mf each required to obtain a capacitance of 5mf will be :-
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4or 5 are required
have anice day ahead
have anice day ahead
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4 2mF capacitors are required to obtain a capacitance of 5mF.
Two in series and Two in parallel which are connected each other in parallel.
Series Capacitance = (1/2) + (1/2) = 1 mF.
Parallel Capacitance = 2 + 2 = 4 mF.
Now these two are connected in parallel.
Final Capacitance = 1 + 4 = 5 mF.
-WonderGirl
Two in series and Two in parallel which are connected each other in parallel.
Series Capacitance = (1/2) + (1/2) = 1 mF.
Parallel Capacitance = 2 + 2 = 4 mF.
Now these two are connected in parallel.
Final Capacitance = 1 + 4 = 5 mF.
-WonderGirl
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