Question

minimum value 5sin^2x + 4cos^2x =

Answer 1

Answer:

Step-by-step explanation:

Let2x=∅ and see

Answer 2

Answer: Minimum value = 4.

Step-by-step explanation:

Since we have given that

$5sin^2x+4cos^2x$

We need to find the minimum value.

In general we know that

if a sin²x+b cos²x is given and if

1) a>b, minimum value = b, maximum value = a

2) a<b, minimum value = a, maximum value = b

here, 5>4

i.e. a>b.

Then, minimum value = 4.