Math, asked by priyadarshi14322, 9 months ago

Minimum value of 5sin2θ + 4cos2θ is

Answers

Answered by agarwallas460

1

Answer:

4

Step-by-step explanation:

lowest value of θ can be 0°.

Therefore, sin0 = 0° and cos0° = 1

Therefore,

5sin2θ + 4cos2θ

= 5sin0° + 4sin0°

= 5(0) + 4(1)

= 0 + 4

= 4

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