Question

Minimum value of f(x) = x2-4x+3 is .....​

Answer 1

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${x}^{2} - 4x + 3 \\ = {x}^{2} - 1x - 3x + 3 \\ = x(x - 1) - 3(x - 1) \\ = (x - 1)(x - 3)$

put both of them equal to zero

$x - 1 = 0 \\ x = 1$

$x - 3 = 0 \\ x = 3$

as you asked fir the minimum value so

$x = 1$

hope it will help you