Minimum value of sin 2x minus root 3 cos 2x is
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Question :- Minimum value of sin 2x - √3cos 2x is = ?
Solution :-
We know that, minimum value of a*sinA + b*cosA is given by :- (-1)√(a² + b²)
So,
comparing sin(2x) - √3cos(2x) with a*sinA + b*cosA we get,
- a = 1
- b = √3
Therefore,
→ Minimum value of sin(2x) - √3cos(2x) = (-1)√(a² + b²)
Putting values we get,
→ Minimum value = (-1)√{1² + (√3)²}
→ Minimum value = (-1)√(1 + 3)
→ Minimum value = (-1)√(4)
→ Minimum value = (-1) * 2
→ Minimum value = (-2) (Ans.)
Hence, Minimum value of sin 2x - √3cos 2x is (-2).
Learn More :-
7. The value of x for the minimum value of √3 cos x +sin x is
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