Question

minimum value of (x-5/3)^2+7/2​

Answer 1

Answer:

we know that square of any number always greater than or equal to zero. so,

${(x - \frac{5}{3} )}^{2} \geqslant 0$

${(x - \frac{5}{3}) }^{2} + \frac{7}{2} \geqslant \frac{7}{2}$

so Min. value is 7/2 . Ans.