Question

Minimum value of x in p(x)=2x^2-x-3

Answer 1

Answer:

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Step-by-step explanation:

2x^2-x-3

2x^2-(3-2)x-3

2x^2-3x+2x-3

x(2x-3)+1(2x-3)

(x+1)(2x-3)

x+1=0 2x-3=0

x=-1,  2x=3

x=-1          x=3/2

Answer 2

Answer:

p(x)= 2x^2-x-3

= 2x^2-3x+2x-3

= [ x(2x-3+1(2×3) ]

= (x+1)(2x-3)

x+1=0, 2x-3=0

x= -1, 2x=3

x= -1,,,, x= 3/2