Math, asked by SharmajiSaheb, 1 year ago

minimum value of y^2-10x-6y+14

Answers

Answered by GauravGumber

1

y²-6y-10x+14
add and sub half of coefficient of y
y²-6y+3²-3²-10x+14
(y-3)²-10x+14
min values should be -10x+14 for (y-3)withmin value equals 0

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